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Open CosmologyPhysics & cosmology: four years, plus a graduate year

The flatness problem

Ω = 1 is an unstable balance point, like a pencil on its tip. For Ω to be anywhere near 1 today, at one second after the Big Bang it must have equalled 1 to about 18 decimal places — and the conventional Big Bang has no reason why.

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Full reading path (39 pages)
  1. Vectors (8.01)
  2. Position and velocity in one dimension (8.01)
  3. Acceleration in one dimension (8.01)
  4. Motion in two dimensions and projectiles (8.01)
  5. The homogeneous expanding universe (8.286)
  6. The Doppler effect and special relativity (8.286)
  7. Cosmological redshift (8.286)
  8. Newton's laws of motion (8.01)
  9. The universal law of gravitation (8.01)
  10. Why a static universe cannot work (8.286)
  11. The expanding sphere and the equation for a(t) (8.286)
  12. The Friedmann equation (8.286)
  13. Open, closed and flat universes (8.286)
  14. The closed universe as a cycloid (8.286)
  15. The age of the universe and the Big Bang singularity (8.286)
  16. The age of a closed universe from H and Ω (8.286)
  17. The open universe and the age of any matter universe (8.286)
  18. Non-Euclidean geometry (8.286)
  19. The metric of a sphere and of a closed universe (8.286)
  20. Curvature and expansion — the Robertson–Walker metric (8.286)
  21. The geometry of open universes (8.286)
  22. The spacetime interval (8.286)
  23. The spacetime metric of the universe (8.286)
  24. The geodesic equation (8.286)
  25. Simplifying the geodesic equation (8.286)
  26. Falling into a black hole (8.286)
  27. Mass, energy and the dilution of radiation (8.286)
  28. Matter–radiation equality and the pressure of light (8.286)
  29. The horizon distance (8.286)
  30. The radiation-dominated universe (8.286)
  31. The cosmological constant and vacuum energy (8.286)
  32. The age of the universe with vacuum energy (8.286)
  33. How bright is a distant supernova? (8.286)
  34. The supernova evidence for acceleration (8.286)
  35. The puzzle of the vacuum energy, and Einstein's mistake about Friedmann (8.286)
  36. Black-body radiation (8.286)
  37. Neutrinos and counting particle species (8.286)
  38. The temperature of the early universe and decoupling (8.286)
  39. The horizon problem (8.286)
On this page · 6 sections
  1. How close to 1 is Ω today?
  2. A pencil balanced on its tip
  3. Why one second?
  4. The calculation
  5. No explanation, only a hope
  6. Summary

The second problem of the conventional Big Bang is the flatness problem: why is Ω0\Omega_0, the present ratio of the actual density to the critical density, anywhere near 1? Like the horizon problem, it can be avoided by assuming something about the initial singularity, but not explained within the conventional theory, whose mechanics are completely well defined.

How close to 1 is Ω today?#

Guth quotes the best value from the Planck team (combined, as for all his Planck numbers, with some other data; the satellite alone gives slightly looser limits):

Planck 2013 limit
Ω0−1=−0.0010±0.0065\Omega_0 - 1 = -0.0010 \pm 0.0065
In words

omega sub 0 minus 1 equals minus 0.0010 plus or minus 0.0065

Source: 8.286 Lecture 21 transcript, p. 12 (board)

The uncertainty is a little more than half a percent. [Planck published this as a value of Ωk=1−Ω\Omega_k = 1 - \Omega, so strictly the central value of Ω0−1\Omega_0 - 1 has the opposite sign; the size of the bound, which is all that matters here, is the same.]

Guth stresses that the argument does not need this precision. When inflation was invented around 1980, Ω was known far less precisely — only to within roughly an order of magnitude, with a lower end around 0.1 — and the problem was nearly as strong. [The transcript gives the 1980 range as "0.1 and 0.2"; since Guth calls it still close to 1 and later says the bound was three orders of magnitude weaker, a range from about 0.1 to about 2 is probably meant.]

A pencil balanced on its tip#

What makes this a problem is the dynamics: Ω=1\Omega = 1 is an unstable equilibrium. An exactly flat universe stays exactly flat, so if Ω=1\Omega = 1 exactly, it stays 1 forever. But if Ω in the early universe were a tiny bit above 1, it would rise and quickly reach infinity — which is what happens when a closed universe reaches its maximum size — and the universe would recollapse. A tiny bit below 1, and Ω would rapidly trail off towards 0. Finding Ω near 1 today is like finding a pencil still almost upright after standing on its tip for a billion years: it must have started incredibly close to vertical. The question is how close.

Why one second?#

Guth evaluates Ω at t=1t = 1 second, following Dicke and Peebles, whose 1979 discussion he credits with introducing the problem. One second is when the processes of nucleosynthesis begin, and the successful predictions of the light-element abundances are real empirical evidence that the conventional model works back to one second after the Big Bang.

The calculation#

Nothing new is needed: only the Friedmann equation and how temperature and density behave in the matter- and radiation-dominated eras. Start from

Friedmann equation, critical density and Ω
H2=8π3Gρ−kc2a2,ρc=3H28πG,Ω≡ρρcH^2 = \frac{8\pi}{3}G\rho - \frac{kc^2}{a^2}, \qquad \rho_c = \frac{3H^2}{8\pi G}, \qquad \Omega \equiv \frac{\rho}{\rho_c}
In words

H squared equals 8 pi over 3 G rho minus kc squared over a squared , rho sub c equals 3H squared over 8 pi G , omega is defined as rho over rho sub c

Source: 8.286 Lecture 21 transcript, p. 14 (board)

together with entropy conservation:

Entropy conservation
aT≈constantaT \approx \text{constant}
In words

aT is approximately constant

Source: 8.286 Lecture 21 transcript, pp. 14–15 (board)

(aTaT changes by a factor of order one when electron–positron pairs disappear — the (4/11)1/3(4/11)^{1/3} of the neutrino temperature — which does not matter here.)

Reshuffling the Friedmann equation, with no approximation, gives a form whose time dependence is easy to read off:

The Friedmann equation rearranged
Ω−1Ω=A T2ρ,A≡3kc28πG a2T2\frac{\Omega - 1}{\Omega} = \frac{A\,T^2}{\rho}, \qquad A \equiv \frac{3kc^2}{8\pi G\,a^2T^2}
In words

omega minus 1 over omega equals A T squared over rho , A is defined as 3kc squared over 8 pi G a squared T squared

Source: 8.286 Lecture 21 transcript, p. 15 (board)

The temperature cancels between AA and T2T^2, so this is exactly the Friedmann equation; it is written this way because AA is (nearly) constant, so (Ω−1)/Ω(\Omega - 1)/\Omega follows T2/ρT^2/\rho. (Divide H2=8π3Gρ−kc2/a2H^2 = \frac{8\pi}{3}G\rho - kc^2/a^2 by 8π3Gρ\frac{8\pi}{3}G\rho to check.) Since Ω is close to 1, the Ω in the denominator hardly matters.

Today. The Planck limit is largest on the negative side, ∣Ω0−1∣≤0.0075|\Omega_0 - 1| \le 0.0075, which gives ∣Ω0−1∣/Ω0≈0.0076|\Omega_0 - 1|/\Omega_0 \approx 0.0076. Guth rounds up:

Present bound
∣Ω0−1Ω0∣<0.01\left|\frac{\Omega_0 - 1}{\Omega_0}\right| < 0.01
In words

omega sub 0 minus 1 over omega sub 0 less than 0.01

Source: 8.286 Lecture 21 transcript, p. 16 (board)

Matter era, from about 50,000 years to now. For a flat matter-dominated universe a∝t2/3a \propto t^{2/3}, with T∝1/aT \propto 1/a and ρ∝1/a3\rho \propto 1/a^3. So T2/ρ∝a∝t2/3T^2/\rho \propto a \propto t^{2/3}: Ω−1\Omega - 1 grows with time. (Matter–radiation equality was about 50,000 years; the class's own estimate was about 47,000.)

Matter era
Ω−1Ω∣50,000 yr≈(50,000 yr13.8×109 yr)2/3Ω−1Ω∣0\left.\frac{\Omega - 1}{\Omega}\right|_{50{,}000\ \text{yr}} \approx \left(\frac{50{,}000\ \text{yr}}{13.8 \times 10^9\ \text{yr}}\right)^{2/3}\left.\frac{\Omega - 1}{\Omega}\right|_0
In words

omega minus 1 over omega sub 50,000 yr is approximately ( 50,000 yr over 13.8 times 10 to the power 9 yr ) to the power 2/3 omega minus 1 over omega sub 0

Source: 8.286 Lecture 21 transcript, p. 17 (board)

Radiation era, from one second to 50,000 years. Now a∝t1/2a \propto t^{1/2} and ρ∝1/a4\rho \propto 1/a^4, so T2/ρ∝a2∝tT^2/\rho \propto a^2 \propto t — growing even faster than in the matter era.

Radiation era
Ω−1Ω∣1 s≈1 s50,000 yrΩ−1Ω∣50,000 yr\left.\frac{\Omega - 1}{\Omega}\right|_{1\ \text{s}} \approx \frac{1\ \text{s}}{50{,}000\ \text{yr}}\left.\frac{\Omega - 1}{\Omega}\right|_{50{,}000\ \text{yr}}
In words

omega minus 1 over omega sub 1 s is approximately 1 s over 50,000 yr omega minus 1 over omega sub 50,000 yr

Source: 8.286 Lecture 21 transcript, p. 18 (board)

Putting the pieces together:

The flatness problem
∣Ω−1∣t=1 s≲10−18|\Omega - 1|_{t = 1\ \text{s}} \lesssim 10^{-18}
In words

| omega minus 1| sub t equals 1 s is less than about 10 to the power minus 18

Source: 8.286 Lecture 21 transcript, p. 18 (board)

To be in the allowed range today, Ω at one second must have equalled 1 to 18 decimal places — and no known physics forces Ω to be 1. With the 1980 knowledge, the present bound was about three orders of magnitude weaker, giving 10−1510^{-15} instead: a thousand times larger, but still an incredibly small number, and the argument sounds exactly the same.

Computed from the scaling laws above: (Ω − 1)/Ω grows like t in the radiation era (slope 1) and like t^(2/3) in the matter era (slope 2/3), from t = 1 s to today (13.8 billion years). The slider sets today's bound: −2 is Planck's 0.01, about 1 is the 1980 situation. With 0.01 today the value at one second is 1.5 × 10⁻¹⁸; the marked points are for that case. Vacuum energy, ignored here as in the lecture, only affects the last few billion years.
Worked example

Pushing the numbers

Use Guth's more accurate figure ∣Ω0−1∣/Ω0=0.0076|\Omega_0 - 1|/\Omega_0 = 0.0076 and the class's equality time of 47,000 years. How close to 1 was Ω at one second? And if the radiation-dominated scaling held all the way back to 10−3510^{-35} s, how close then?

Matter era

t0=13.8×109t_0 = 13.8 \times 10^9 yr. (47,000/13.8×109)2/3=(3.41×10−6)2/3=2.26×10−4(47{,}000/13.8 \times 10^9)^{2/3} = (3.41 \times 10^{-6})^{2/3} = 2.26 \times 10^{-4}.

Radiation era

47,000 yr =1.48×1012= 1.48 \times 10^{12} s, so the factor is 6.74×10−136.74 \times 10^{-13}.

At one second

0.0076×2.26×10−4×6.74×10−13=1.2×10−180.0076 \times 2.26 \times 10^{-4} \times 6.74 \times 10^{-13} = 1.2 \times 10^{-18}.

At 10⁻³⁵ s

In the radiation era the quantity is proportional to tt, so it shrinks by another factor 103510^{35}: 1.2×10−531.2 \times 10^{-53}. (This extrapolation assumes nothing but radiation-dominated expansion before one second — exactly what inflation will change.)

No explanation, only a hope#

As with the horizon problem, ignorance can be blamed on the singularity: assume the universe started with Ω exactly 1, or 1 to some extraordinary accuracy. But that is a hope for an explanation, not an explanation. Inflation, Guth says, provides a mechanism that drives the early universe towards Ω=1\Omega = 1.

A student suggests that Ω=1\Omega = 1 is natural because a flat universe has zero total energy. Guth disagrees: a closed universe also has zero total energy, so Ω=1\Omega = 1 is not special that way. And kk can take any value on the real line — positive (closed) or negative (open) — while exactly flat is the single point k=0k = 0, hardly what you would expect from a random draw. Ultimately we can't know without understanding the singularity; you are free to speculate, but inflation removes the need to.

Summary#

  • Ω=1\Omega = 1 is an unstable equilibrium: any departure grows with time.
  • Exactly rewritten, the Friedmann equation reads (Ω−1)/Ω=AT2/ρ(\Omega - 1)/\Omega = AT^2/\rho with A=3kc2/(8πGa2T2)A = 3kc^2/(8\pi Ga^2T^2) nearly constant, so (Ω−1)/Ω∝t2/3(\Omega - 1)/\Omega \propto t^{2/3} in the matter era and ∝t\propto t in the radiation era.
  • With ∣Ω0−1∣<0.01|\Omega_0 - 1| < 0.01, at t=1t = 1 s (the start of nucleosynthesis) ∣Ω−1∣≲10−18|\Omega - 1| \lesssim 10^{-18}; even 1980's rough knowledge gives 10−1510^{-15}.
  • The conventional Big Bang can only assume this; inflation explains it.

Symbols on this page

Show the 22 symbols used here
π\pi pi
The ratio of a circle's circumference to its diameter, π ≈ 3.14159. Say it: “pi”.
ρ\rho rho
Density: mass (or energy divided by c²) per unit volume. ρ_c is the critical density, ρ̄ the mean density. Say it: “rho”.
Ω\Omega capital omega
The density parameter Ω = ρ/ρ_c. Subscripts pick one ingredient: Ω_m matter, Ω_vac (or Ω_Λ) vacuum energy, Ω_r radiation, Ω_k curvature. Say it: “omega”.
≈\approx approximately equal
Is approximately equal to. Say it: “is approximately”.
∝\propto proportional to
Is proportional to: doubling one doubles the other. Say it: “is proportional to”.
≡\equiv identical to
Is defined as (or is identically equal to). Say it: “is defined as”.
≲\lesssim less than about
Is less than, or roughly equal to. Say it: “is less than about”.
≤\le less than or equal
Is less than or equal to. Say it: “is less than or equal to”.
±\pm plus or minus
Plus or minus: both signs, or an uncertainty (67.3 ± 1.2). Say it: “plus or minus”.
×\times times
Times (multiplication). Between two vectors: the cross product. Say it: “times”.
log⁡\log logarithm
Logarithm; log₁₀ is the base-10 logarithm. Say it: “log”.
aa a
The scale factor a(t): how much the universe has expanded. Physical distance = a × comoving distance (Guth's units: metres per notch). Say it: “a”.
HH H
The Hubble parameter H = ȧ/a: the expansion rate of the universe at a given time. Say it: “H”.
GG G
Newton's gravitational constant, G ≈ 6.674 × 10⁻¹¹ m³ kg⁻¹ s⁻². Say it: “G”.
cc c
The speed of light, c ≈ 2.998 × 10⁸ m/s. Say it: “c”.
kk k
The curvature constant: k > 0 closed, k = 0 flat, k < 0 open (Guth's units: 1/notch²). Say it: “k”.
TT T
Temperature, in kelvin. Say it: “T”.
H0H_{0} Hubble constant
The Hubble constant: today's value of H, about 67–73 km/s/Mpc. Say it: “H nought”.
t0t_{0} today
Today: the present time, about 13.8 billion years after the Big Bang in the real universe (simple models on some pages give other ages). Say it: “t nought”.
ρc\rho_{c} critical density
The critical density, 3H²/(8πG): the density of a flat universe (about 9 × 10⁻²⁷ kg/m³ today). Say it: “rho c”.
Ωk,0\Omega_{k,0} curvature density parameter
The curvature term written like a density parameter, −kc²/(a²H²); ',0' means today. Zero for a flat universe. Say it: “omega k”.
Ω0\Omega_{0} Omega today
Today's value of Ω, the total density as a fraction of the critical density. Say it: “omega nought”.

Tap or click a symbol in a formula to see the same explanation. All symbols: symbols and notation.

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Check your understanding

  1. Why is Ω = 1 called an unstable equilibrium?
  2. Starting from the Friedmann equation, what is (Ω−1)/Ω(\Omega - 1)/\Omega?
  3. How does (Ω−1)/Ω(\Omega - 1)/\Omega grow in the radiation era?
  4. Using today's bound ∣Ω0−1∣≲0.01|\Omega_0 - 1| \lesssim 0.01, how close to 1 must Ω have been at t=1t = 1 s?
  5. Was the flatness problem already a problem around 1980, when Ω was only known roughly?
0 of 5 answered

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